It depends on what you are going to do with the tube or the rod. But in a rotational or torsional application the tube is stiffer. So the rod is stiffer in a simple cantilever application for flexural stress and in the mechanical stiffness application the rod is still stiffer. The smaller flexural stress means a stiffer member. So this would give you a smaller flexural stress in the rod. I think that we need to look at the flexural stresses/ the extreme fiber stresses in this situation.Įquation for calculating the flexural stresses/ the extreme fiber stresses in the tube or the rod. the mass moment of inertia of the tube and the rod and found that the tube and rod's mass moment of inertia are the same, ( 12-lbm-in^2). I am looking, which is stiffer the tube or the rod and lets say that the lengths are 12" long for both tube and rod and both weigh the same 1-lbm. The simulation technique, presented hereinafter, is a novel methodology for calculating the bending stiffness of composite tube that is based on five clear. This give you a cross sectional area of 1.69 x 10^-4 sqin. Formula MI for Solid Round Beams (pi (OD4 - ID4))64 Deflection (length 3 force) (3 E MI) Bending Stress (force length)(MI / (0.5 height)). a rod of the same material in a simple cantilever application.
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